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How do we solve a linear equation by keeping it balanced, and how do we turn a word problem into one?

Solve linear equations in one unknown, including those with brackets and fractions, and form linear equations from word problems

A focused answer to the N(A)-Level Mathematics outcome on linear equations. The balance method, equations with brackets and fractions, checking solutions, and forming equations from words.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to solve linear equations in one unknown (equations where the unknown appears only to the first power), including ones with brackets and fractions, and to form a linear equation from a word problem and solve it. Solving equations is the engine of algebra: graphs, geometry and statistics all lead back to equations.

The answer

The balance method

An equation says two expressions are equal. To keep it true, whatever you do to one side you must do to the other. The goal is to get the unknown by itself on one side.

Use inverse operations to undo what has been done to the unknown:

  • The inverse of adding is subtracting, and the reverse.
  • The inverse of multiplying is dividing, and the reverse.

For 3x+5=203x + 5 = 20, subtract 55 from both sides to get 3x=153x = 15, then divide both sides by 33 to get x=5x = 5.

Unknowns on both sides

When the unknown appears on both sides, first collect the unknown terms on one side and the numbers on the other. For 7xβˆ’4=3x+127x - 4 = 3x + 12, subtract 3x3x from both sides to get 4xβˆ’4=124x - 4 = 12, add 44 to get 4x=164x = 16, then divide by 44 to get x=4x = 4.

Equations with brackets

Expand the brackets first, then solve as usual. For 2(x+3)=142(x + 3) = 14, expand to 2x+6=142x + 6 = 14, subtract 66 to get 2x=82x = 8, then divide by 22 to get x=4x = 4.

Equations with fractions

Multiply every term by the denominator to clear the fraction. For x3=4\dfrac{x}{3} = 4, multiply both sides by 33 to get x=12x = 12. For x+12=5\dfrac{x + 1}{2} = 5, multiply both sides by 22 to get x+1=10x + 1 = 10, so x=9x = 9.

Checking your solution

Substitute your answer back into the original equation. If both sides give the same value, the solution is correct. This catches sign and arithmetic slips and is quick to do.

Forming equations from words

Translate a word problem in three steps: let a letter stand for the unknown, write the relationship as an equation, then solve it. Phrases such as "is", "gives" or "equals" mark where the equals sign goes.

Examples in context

Example 1. An age problem. Mei is 33 years older than her brother, and together their ages add to 2121. Let the brother be xx, so Mei is x+3x + 3 and x+(x+3)=21x + (x + 3) = 21. This gives 2x+3=212x + 3 = 21, so 2x=182x = 18 and x=9x = 9. The brother is 99 and Mei is 1212. Defining one unknown and writing the other in terms of it keeps the equation linear.

Example 2. A geometry link. Two angles on a straight line are 2x2x and x+30x + 30. Since angles on a straight line sum to 180∘180^\circ, we have 2x+x+30=1802x + x + 30 = 180, so 3x=1503x = 150 and x=50x = 50. Many geometry questions reduce to a linear equation once the angle fact is written down.

Try this

  • Cue. Solve 4x+9=334x + 9 = 33. Subtract 99 to get 4x=244x = 24, then divide by 44 to get x=6x = 6.
  • Cue. Solve 3(xβˆ’2)=183(x - 2) = 18. Expand to 3xβˆ’6=183x - 6 = 18, add 66, divide by 33 to get x=8x = 8.
  • Cue. Solve x5+1=4\dfrac{x}{5} + 1 = 4. Subtract 11 to get x5=3\dfrac{x}{5} = 3, then multiply by 55 to get x=15x = 15.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksSolve the equation 5xβˆ’7=2x+85x - 7 = 2x + 8.
Show worked answer β†’

Collect the xx terms on one side and the numbers on the other.

Subtract 2x2x from both sides: 5xβˆ’2xβˆ’7=85x - 2x - 7 = 8, so 3xβˆ’7=83x - 7 = 8.

Add 77 to both sides: 3x=153x = 15.

Divide both sides by 33: x=5x = 5.

Check: 5(5)βˆ’7=185(5) - 7 = 18 and 2(5)+8=182(5) + 8 = 18. Both sides agree.

What markers reward: doing the same operation to both sides at each step, isolating xx, and the correct value. A substitution check confirms the answer and is good exam practice.

Original4 marksI think of a number. When I multiply it by 44 and subtract 33, the result is 2525. Form an equation and solve it to find the number.
Show worked answer β†’

Let the number be xx.

"Multiply by 44 and subtract 33 gives 2525" becomes 4xβˆ’3=254x - 3 = 25.

Add 33 to both sides: 4x=284x = 28.

Divide by 44: x=7x = 7.

Check: 4(7)βˆ’3=254(7) - 3 = 25, which matches.

What markers reward: defining the unknown with a letter, translating the words into a correct equation, solving by the balance method, and a clear final answer. Stating "let the number be xx" earns the forming mark.

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