How do we solve a trigonometric equation and find all the angles in a given range?
Solve simple trigonometric equations within a stated range using the basic angle and the quadrant rule
A focused answer to the N(A)-Level Additional Mathematics outcome on trigonometric equations. Find the basic angle, use the quadrant sign rule to locate all solutions, and list every angle within a stated range.
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What this dot point is asking
SEAB wants you to solve a trigonometric equation such as and find every solution within a stated range (often to ). The method is always the same: find the basic angle from the positive value, decide which quadrants the solutions lie in from the sign, then write down each angle in range. The most common error is giving only the calculator answer and missing the others.
The answer
Step one: find the basic angle
The basic angle (reference angle) is the acute angle you get by taking the inverse trig function of the positive value:
Always use the positive value here; the sign of the original number is handled separately by the quadrants. For example, for the basic angle is .
Step two: choose the quadrants from the sign
The sign of the right-hand side tells you which quadrants the solutions are in, using "All, Sine, Tangent, Cosine":
- positive: quadrants 1 and 2; negative: quadrants 3 and 4.
- positive: quadrants 1 and 4; negative: quadrants 2 and 3.
- positive: quadrants 1 and 3; negative: quadrants 2 and 4.
Step three: build the angles in each quadrant
With basic angle , the angle in each quadrant is:
- Quadrant 1:
- Quadrant 2:
- Quadrant 3:
- Quadrant 4:
Write down the two (or more) that fall in the chosen quadrants and lie within the given range.
Handling a wider range or a multiple angle
If the range is larger (say up to ), keep adding to each solution while it stays in range. If the equation is in a multiple angle like , solve for over the stretched range first, then divide each answer by .
Examples in context
Example 1. After applying an identity. A question may first need an identity to reduce to , which then splits into two standard equations. So the identity work and the equation-solving method combine in fuller questions.
Example 2. Modelling periodic motion. The height of a point on a turning wheel, or the depth of a tide, follows a sine model. Finding the times when the height takes a particular value means solving a trigonometric equation over a time range, which is exactly this skill applied to a real periodic situation.
Try this
Q1. Solve for . [2 marks]
- Cue. Basic angle ; cosine positive in quadrants 1 and 4, so and .
Q2. Solve for . [2 marks]
- Cue. Basic angle ; tangent positive in quadrants 1 and 3, so and .
Q3. Solve for . [2 marks]
- Cue. at , and .
Exam-style practice questions
Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Original3 marksSolve for .Show worked answer →
Basic angle: .
Sine is positive in the first and second quadrants, so and .
What markers reward: finding the basic angle , recognising sine is positive in quadrants 1 and 2, and giving both solutions and within the range.
Original3 marksSolve for .Show worked answer →
Basic angle: (use the positive value for the basic angle).
Cosine is negative in the second and third quadrants, so and .
What markers reward: taking the basic angle from the positive value, placing solutions in the quadrants where cosine is negative, and giving and .
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