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What are the basic trigonometric identities, and how do we use them to simplify or prove expressions?

Use the identities tan equals sin over cos and sin squared plus cos squared equals one to simplify expressions and prove simple results

A focused answer to the N(A)-Level Additional Mathematics outcome on trigonometric identities. The quotient identity, the Pythagorean identity, and how to use them to simplify expressions and prove simple results.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to know the two basic trigonometric identities and use them to simplify expressions, find one ratio from another, and prove simple results. An identity is true for every value of the angle, unlike an equation, which is only true for particular angles. The two identities you need are the quotient identity and the Pythagorean identity, and almost every simplification leans on one of them.

The answer

The quotient identity

Tangent is defined as sine divided by cosine:

tanθ=sinθcosθ\tan\theta = \frac{\sin\theta}{\cos\theta}

This lets you replace a tangent by a sine-over-cosine fraction, or the other way around, whenever it helps tidy an expression.

The Pythagorean identity

For every angle:

sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1

(The notation sin2θ\sin^2\theta means (sinθ)2(\sin\theta)^2.) This comes straight from the unit circle: the point (cosθ,sinθ)(\cos\theta, \sin\theta) lies on a circle of radius 11, and Pythagoras gives x2+y2=1x^2 + y^2 = 1. Two rearrangements are constantly useful:

sin2θ=1cos2θ,cos2θ=1sin2θ\sin^2\theta = 1 - \cos^2\theta, \qquad \cos^2\theta = 1 - \sin^2\theta

Finding one ratio from another

If you know one ratio and the quadrant, the Pythagorean identity gives the others. Solve for the square, take the square root, and choose the sign from the quadrant. The quotient identity then gives tangent.

Proving an identity

To prove an identity, work on one side only (usually the more complicated one) and use the two identities, plus ordinary algebra, until it matches the other side. Do not move terms across the equals sign as if solving an equation; instead transform one side step by step. Writing tanθ\tan\theta as sinθcosθ\dfrac{\sin\theta}{\cos\theta} early often unlocks the proof.

Examples in context

Example 1. Simplifying before solving. Many trigonometric equations look hard until an identity simplifies them. Replacing 1cos2θ1 - \cos^2\theta with sin2θ\sin^2\theta, for instance, can turn a mixed equation into one involving a single function, which is then solvable. So identities are the preparation step for the equation-solving topic.

Example 2. Right-triangle shortcut. If a right triangle gives sinθ=35\sin\theta = \tfrac{3}{5}, the identity immediately yields cosθ=45\cos\theta = \tfrac{4}{5} without redrawing the triangle, and then tanθ=34\tan\theta = \tfrac{3}{4}. The identities let you move between ratios quickly in geometry and physics problems.

Try this

Q1. Given cosθ=0.8\cos\theta = 0.8 and θ\theta acute, find sinθ\sin\theta. [2 marks]

  • Cue. sin2θ=10.64=0.36\sin^2\theta = 1 - 0.64 = 0.36, so sinθ=0.6\sin\theta = 0.6.

Q2. Simplify 1cos2θ1 - \cos^2\theta. [1 mark]

  • Cue. By the Pythagorean identity, 1cos2θ=sin2θ1 - \cos^2\theta = \sin^2\theta.

Q3. Prove that tanθcosθ=sinθ\tan\theta\,\cos\theta = \sin\theta. [2 marks]

  • Cue. Left side =sinθcosθ×cosθ=sinθ= \dfrac{\sin\theta}{\cos\theta}\times\cos\theta = \sin\theta, the right side.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original2 marksGiven that sinθ=0.6\sin\theta = 0.6 and θ\theta is acute, find cosθ\cos\theta.
Show worked answer →

Use sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1, so cos2θ=10.62=10.36=0.64\cos^2\theta = 1 - 0.6^2 = 1 - 0.36 = 0.64.

Then cosθ=0.64=0.8\cos\theta = \sqrt{0.64} = 0.8 (positive because θ\theta is acute).

What markers reward: applying the Pythagorean identity, computing cos2θ=0.64\cos^2\theta = 0.64, and taking the positive root because the angle is acute.

Original3 marksProve the identity sinθcosθ×cosθ=sinθ\dfrac{\sin\theta}{\cos\theta} \times \cos\theta = \sin\theta.
Show worked answer →

Start with the left-hand side: sinθcosθ×cosθ\dfrac{\sin\theta}{\cos\theta} \times \cos\theta.

The cosθ\cos\theta in the numerator and denominator cancel, leaving sinθ\sin\theta, which equals the right-hand side.

What markers reward: working on one side only, cancelling cosθ\cos\theta cleanly, and reaching the right-hand side to complete the proof.

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