Skip to main content
SingaporePhysicsSyllabus dot point

What is pressure, and how does the pressure in a liquid change with depth?

Define pressure, apply pressure equals force over area, and calculate the pressure due to a liquid column

A focused answer to the O-Level Physics outcome on pressure. Pressure as force per unit area, the pascal, why pressure increases with depth in a liquid, and the relationship for the pressure of a liquid column.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

Have a quick question? Jump to the Q&A page

Jump to a section
  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to define pressure, to use p=F/Ap = F/A in calculations, and to explain and calculate how the pressure in a liquid increases with depth using p=hρgp = h\rho g. The big idea is that the same force spread over a smaller area gives a larger pressure, and that a tall column of liquid presses harder at the bottom because of the weight of the liquid above.

The answer

What pressure is

Pressure is the force acting per unit area, where the force is perpendicular to the surface:

p=FAp = \frac{F}{A}

Force is in newtons and area in square metres, so the unit of pressure is the pascal (Pa\text{Pa}), where 1 Pa=1 N m21\ \text{Pa} = 1\ \text{N m}^{-2}. For the same force, a smaller area gives a larger pressure, which is why a sharp knife (small area) cuts more easily than a blunt one.

Pressure in liquids

A liquid exerts pressure on any surface in contact with it. This pressure:

  • increases with depth, because there is more liquid pressing down from above,
  • acts equally in all directions at a given depth,
  • depends on the density of the liquid, not on the shape or width of the container.

The liquid column relationship

The pressure due to a column of liquid of height (depth) hh is:

p=hρgp = h\rho g

where ρ\rho is the density of the liquid and gg the gravitational field strength. This is the extra pressure caused by the liquid; the total pressure also includes the atmospheric pressure pushing down on the surface.

Why depth, not shape, matters

Two containers of different shapes filled to the same depth with the same liquid have the same pressure at the bottom, because p=hρgp = h\rho g depends only on the depth, the density, and gg, not on how wide the container is or how much liquid it holds.

Examples in context

Example 1. Dam walls. A dam is built much thicker at the bottom than at the top, because the water pressure increases with depth (p=hρgp = h\rho g). The deepest water presses hardest, so the wall must be strongest there to withstand the larger force.

Example 2. Sharp versus blunt. Pressing a drawing pin pushes the same force onto a tiny point area, giving a huge pressure that pierces the board, while the broad head spreads the force on your thumb over a large area, giving a small, comfortable pressure. Same force, very different pressures, because of the difference in area.

Try this

Q1. A force of 200 N200\ \text{N} acts on an area of 0.50 m20.50\ \text{m}^2. Calculate the pressure. [2 marks]

  • Cue. p=FA=2000.50=400 Pap = \dfrac{F}{A} = \dfrac{200}{0.50} = 400\ \text{Pa}.

Q2. Find the pressure at the bottom of a 5.0 m5.0\ \text{m} deep pool of water (ρ=1000 kg m3\rho = 1000\ \text{kg m}^{-3}, g=10 N kg1g = 10\ \text{N kg}^{-1}). [2 marks]

  • Cue. p=hρg=5.0×1000×10=50000 Pap = h\rho g = 5.0 \times 1000 \times 10 = 50\,000\ \text{Pa}.

Q3. Explain why pressure in a liquid increases with depth. [2 marks]

  • Cue. The deeper you go, the greater the weight of liquid above pressing down, so the pressure is larger.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marksA box weighing 600 N600\ \text{N} stands on the floor. Its base measures 1.5 m1.5\ \text{m} by 0.80 m0.80\ \text{m}. (a) Find the area of the base. (b) Find the pressure the box exerts on the floor.
Show worked answer →

(a) Area of the base: A=1.5×0.80=1.2 m2A = 1.5 \times 0.80 = 1.2\ \text{m}^2.

(b) Pressure: p=FA=6001.2=500 Pap = \dfrac{F}{A} = \dfrac{600}{1.2} = 500\ \text{Pa}.

Markers reward the base area, pressure as force over area, and the answer in pascals (newtons per square metre).

Original5 marksA diver descends to a depth of 20 m20\ \text{m} in sea water of density 1030 kg m31030\ \text{kg m}^{-3}. Take g=10 N kg1g = 10\ \text{N kg}^{-1}. (a) Calculate the pressure due to the water at that depth. (b) Explain why the total pressure on the diver is larger than this value.
Show worked answer →

(a) Pressure of a liquid column: p=hρg=20×1030×10=206000 Pap = h\rho g = 20 \times 1030 \times 10 = 206\,000\ \text{Pa} (about 2.1×105 Pa2.1 \times 10^5\ \text{Pa}).

(b) The total pressure is larger because the atmosphere also presses down on the surface of the sea. The total is the water pressure plus the atmospheric pressure acting on the surface above the diver.

Markers reward p=hρgp = h\rho g with the correct substitution and units, and the point that atmospheric pressure must be added to the liquid pressure to get the total.

Related dot points