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What does it mean for an amplifier to have gain, and how is that gain expressed as a ratio and in decibels?

Define voltage gain as a ratio, calculate it, and express it in decibels using the gain equation

A focused answer to the O-Level Electronics outcome on amplifier gain. Voltage gain as the ratio of output to input, calculating it, and expressing gain in decibels.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to define the voltage gain of an amplifier as the ratio of output voltage to input voltage, to calculate it, and to express it in decibels. The central insight is that gain measures how many times bigger the output is than the input, and that because gains range over a huge span, they are often quoted on the logarithmic decibel scale.

The answer

What gain means

An amplifier produces an output signal that is a larger copy of its input signal. The voltage gain tells you how many times larger the output is than the input:

Av=VoutVinA_v = \frac{V_{out}}{V_{in}}

Gain is a pure number with no unit, because it is the ratio of two voltages. A gain of 200200 means the output voltage is 200200 times the input voltage.

Calculating gain

To find the gain, divide the output voltage by the input voltage, making sure both are in the same unit first. A small input of 20 mV20\ \text{mV} and an output of 4 V4\ \text{V} give a gain of 4/0.020=2004 / 0.020 = 200. The same formula rearranges to find the output from the input and gain, Vout=AvVinV_{out} = A_v V_{in}, or the input from the output and gain.

Gain in decibels

Gains can be enormous, so they are often expressed on a logarithmic scale in decibels (dB\text{dB}). For a voltage gain:

AdB=20log10 ⁣(VoutVin)=20log10(Av)A_{dB} = 20\log_{10}\!\left(\frac{V_{out}}{V_{in}}\right) = 20\log_{10}(A_v)

The factor is 2020 for voltage (and current) ratios. Some useful values: a gain of 1010 is 20 dB20\ \text{dB}, a gain of 100100 is 40 dB40\ \text{dB}, and a gain of 10001000 is 60 dB60\ \text{dB}. Each extra factor of ten in the ratio adds 20 dB20\ \text{dB}.

Amplification and attenuation

If the output is larger than the input, the gain is greater than one and the decibel value is positive: this is amplification. If the output is smaller than the input, the gain is less than one and the decibel value is negative: this is attenuation. A gain of exactly one is 0 dB0\ \text{dB}, meaning no change in size.

Examples in context

Example 1. A hearing aid. A hearing aid amplifies a faint sound into one loud enough to hear, with its amplification often quoted in decibels because the ear itself responds logarithmically to loudness. A gain of 40 dB40\ \text{dB} means the signal voltage is multiplied by 100100, turning a whisper into a clearly audible sound.

Example 2. An audio mixing desk. Each channel of a mixing desk has a gain control calibrated in decibels. Setting a channel to +6 dB+6\ \text{dB} roughly doubles its voltage, while 6 dB-6\ \text{dB} roughly halves it. The decibel scale lets engineers add and compare gains across many stages without juggling huge ratios.

Try this

  • Cue. An amplifier has Vin=50 mVV_{in} = 50\ \text{mV} and Vout=5.0 VV_{out} = 5.0\ \text{V}. Find the gain. Convert and divide: Av=5.0/0.050=100A_v = 5.0 / 0.050 = 100.

  • Cue. Express a voltage gain of 1010 in decibels. AdB=20log10(10)=20×1=20 dBA_{dB} = 20\log_{10}(10) = 20 \times 1 = 20\ \text{dB}.

  • Cue. State what a gain of 0 dB0\ \text{dB} means. The output equals the input (Av=1A_v = 1), so there is no amplification or attenuation; the signal size is unchanged.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksAn amplifier has an input voltage of 20 mV20\ \text{mV} and an output voltage of 4.0 V4.0\ \text{V}. Calculate its voltage gain.
Show worked answer →

Both voltages must be in the same unit. Convert: 20 mV=0.020 V20\ \text{mV} = 0.020\ \text{V}.

Voltage gain is output divided by input: Av=VoutVin=4.00.020=200A_v = \dfrac{V_{out}}{V_{in}} = \dfrac{4.0}{0.020} = 200.

What markers reward: converting to the same unit, the ratio Vout/VinV_{out}/V_{in}, and the answer 200200 (a pure number with no unit). Gain has no unit because it is a ratio of two voltages.

Original4 marksAn amplifier has a voltage gain of 100100. (a) Express this gain in decibels. (b) State what is meant by a negative gain in decibels.
Show worked answer →

(a) Gain in decibels is AdB=20log10(Av)=20log10(100)=20×2=40 dBA_{dB} = 20\log_{10}(A_v) = 20\log_{10}(100) = 20 \times 2 = 40\ \text{dB}.

(b) A negative decibel value means the output is smaller than the input, that is attenuation rather than amplification (a voltage ratio less than one gives a negative logarithm).

What markers reward: the formula 20log10(Av)20\log_{10}(A_v) giving 40 dB40\ \text{dB}, and explaining a negative decibel figure as attenuation (gain less than one). Forgetting the factor of 2020 is the usual slip.

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