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How do feedback resistors set the gain of an op-amp amplifier, and how do the inverting and non-inverting configurations differ?

Apply the gain equations for the inverting and non-inverting op-amp amplifier and explain the role of negative feedback

A focused answer to the O-Level Electronics outcome on op-amp amplifiers. The inverting and non-inverting gain equations, the role of negative feedback, and choosing resistors for a wanted gain.

Generated by Claude Opus 4.89 min answer

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to apply the gain equations for the inverting and non-inverting op-amp amplifier and to explain the role of negative feedback. The central insight is that connecting a feedback resistor from the output back to the inverting input tames the op-amp's enormous open-loop gain into a controlled, predictable gain set entirely by the resistor values.

The answer

Negative feedback

On its own, an op-amp has a huge but imprecise open-loop gain. To make a useful amplifier, a fraction of the output is fed back to the inverting (-) input through a feedback resistor. Because it returns to the inverting input, this is negative feedback: it opposes change. Negative feedback trades away the unwanted excess gain in exchange for:

  • A stable, predictable gain set by the resistor values, not by the op-amp's variable open-loop gain.
  • Less distortion, so the output is a more faithful, larger copy of the input.

This is why nearly every linear amplifier uses negative feedback.

The inverting amplifier

In the inverting amplifier, the input signal is applied through an input resistor RinR_{in} to the inverting input, and the non-inverting input is held at 0 V0\ \text{V}. The gain is:

Av=RfRinA_v = -\frac{R_f}{R_{in}}

The minus sign means the output is inverted: a positive input gives a negative output, and the waveform is turned upside down. The size of the gain is the ratio of the feedback resistor to the input resistor.

The non-inverting amplifier

In the non-inverting amplifier, the input signal is applied to the non-inverting (++) input, and the feedback network (RfR_f and a resistor RinR_{in} to 0 V0\ \text{V}) sets the gain. The gain is:

Av=1+RfRinA_v = 1 + \frac{R_f}{R_{in}}

There is no minus sign, so the output is in phase with the input (not inverted), and the gain is always at least one.

Choosing resistors for a wanted gain

To design for a particular gain, pick the ratio of the resistors. For an inverting amplifier of gain 10-10, make RfR_f ten times RinR_{in} (for example 100 kΩ100\ \text{k}\Omega and 10 kΩ10\ \text{k}\Omega). For a non-inverting amplifier of gain 66, make RfR_f five times RinR_{in}, since the formula adds one. The actual values are usually in the kilohm to megohm range.

Examples in context

Example 1. A sensor pre-amplifier. A thermocouple produces only a few millivolts. A non-inverting amplifier with a gain of, say, 100100 boosts this to a useful level for a meter or analogue-to-digital converter, while negative feedback keeps the gain accurate and steady over temperature. The resistor ratio, not the op-amp, fixes the gain a designer can rely on.

Example 2. An audio tone stage. An inverting amplifier sets the volume of a stage by the ratio of two resistors, and the inversion is harmless for audio because the ear cannot hear the phase flip. Swapping the input resistor for a potentiometer turns the fixed gain into an adjustable volume control, a common building block in audio equipment.

Try this

  • Cue. An inverting amplifier has Rf=47 kΩR_f = 47\ \text{k}\Omega and Rin=4.7 kΩR_{in} = 4.7\ \text{k}\Omega. Find the gain. Av=Rf/Rin=47/4.7=10A_v = -R_f/R_{in} = -47/4.7 = -10.

  • Cue. A non-inverting amplifier has Rf=90 kΩR_f = 90\ \text{k}\Omega and Rin=10 kΩR_{in} = 10\ \text{k}\Omega. Find the gain. Av=1+Rf/Rin=1+9=10A_v = 1 + R_f/R_{in} = 1 + 9 = 10.

  • Cue. State one advantage of using negative feedback in an amplifier. The gain becomes stable and predictable, set by the resistor values rather than the op-amp's variable open-loop gain, with less distortion.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marksAn inverting amplifier uses a feedback resistor of 100 kΩ100\ \text{k}\Omega and an input resistor of 10 kΩ10\ \text{k}\Omega. (a) Calculate the voltage gain. (b) If the input is +0.20 V+0.20\ \text{V}, state the output voltage.
Show worked answer →

(a) The inverting gain is Av=RfRin=10010=10A_v = -\dfrac{R_f}{R_{in}} = -\dfrac{100}{10} = -10. The minus sign shows inversion.

(b) Output is gain times input: Vout=Av×Vin=10×0.20=2.0 VV_{out} = A_v \times V_{in} = -10 \times 0.20 = -2.0\ \text{V}. The output is inverted in sign.

What markers reward: the inverting gain formula giving 10-10, and applying it to get 2.0 V-2.0\ \text{V}, including the sign change. The magnitude is 1010 and the sign is negative.

Original4 marksA non-inverting amplifier uses a feedback resistor of 50 kΩ50\ \text{k}\Omega and a resistor of 10 kΩ10\ \text{k}\Omega from the inverting input to 0 V0\ \text{V}. (a) Calculate the voltage gain. (b) Explain one advantage of using negative feedback to set the gain.
Show worked answer →

(a) The non-inverting gain is Av=1+RfRin=1+5010=1+5=6A_v = 1 + \dfrac{R_f}{R_{in}} = 1 + \dfrac{50}{10} = 1 + 5 = 6.

(b) Negative feedback makes the gain depend only on the resistor values, not on the op-amp's exact (and variable) open-loop gain. This gives a stable, predictable gain and reduces distortion.

What markers reward: the non-inverting formula giving a gain of 66, and an advantage such as a stable, predictable gain set by resistors, less distortion, or wider bandwidth.

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