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How are chemical formulae built from ionic charges, and how is a chemical equation balanced?

Write formulae of ionic compounds from the charges on their ions, construct and balance chemical equations, and add state symbols

A focused answer to the O-Level Chemistry outcome on formulae and equations. Building ionic formulae by balancing charges, balancing chemical equations atom by atom, and adding the correct state symbols.

Generated by Claude Opus 4.88 min answer

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to write the formula of an ionic compound by balancing the charges on its ions, construct and balance chemical equations so that atoms are conserved, and add the correct state symbols. These are the writing skills of chemistry: every calculation, every reaction and every exam answer depends on a correct formula and a balanced equation.

The answer

Writing ionic formulae from charges

An ionic compound is electrically neutral, so the total positive charge must equal the total negative charge. To write the formula:

  1. Write the symbol of each ion with its charge (for example Ca2+\text{Ca}^{2+} and Clβˆ’\text{Cl}^-).
  2. Find how many of each ion are needed so the charges cancel. Here one Ca2+\text{Ca}^{2+} (+2+2) needs two Clβˆ’\text{Cl}^- (βˆ’2-2 total).
  3. Write the numbers as subscripts: CaCl2\text{CaCl}_2.

A quick method is to swap the charge numbers as subscripts (the "cross-over" rule), then simplify to the smallest whole-number ratio. Compound ions such as sulfate (SO42βˆ’\text{SO}_4^{2-}), nitrate (NO3βˆ’\text{NO}_3^-) and carbonate (CO32βˆ’\text{CO}_3^{2-}) keep their group together; if you need more than one, put it in brackets, as in calcium nitrate Ca(NO3)2\text{Ca(NO}_3)_2.

Balancing chemical equations

A chemical equation must have the same number of atoms of each element on both sides, because atoms are not created or destroyed (conservation of mass). You balance by putting whole-number coefficients in front of the formulae. You may never change a formula (the subscripts) to balance, only the big numbers in front.

A reliable order is:

  1. Write the correct formulae of all reactants and products (do not change these).
  2. Balance the metals first, then the non-metals, leaving oxygen and hydrogen toward the end.
  3. Balance oxygen and hydrogen last, adjusting coefficients.
  4. Check every element, and simplify the coefficients to the smallest whole-number ratio.

State symbols

State symbols are added in brackets after each formula to show the physical state:

  • (s)(s) solid
  • (l)(l) liquid
  • (g)(g) gas
  • (aq)(aq) aqueous (dissolved in water)

For example, the neutralisation of hydrochloric acid by sodium hydroxide is written HCl(aq)+NaOH(aq)β†’NaCl(aq)+H2O(l)\text{HCl}(aq) + \text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l).

Examples in context

Example 1. Combustion equations. Burning a fuel such as propane is balanced by doing carbon first, then hydrogen, then oxygen, giving C3H8+5O2β†’3CO2+4H2O\text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}. The order (carbon, hydrogen, oxygen last) makes balancing organic combustion straightforward and recurs throughout the organic topic.

Example 2. Ionic equations in qualitative analysis. When silver nitrate solution forms a precipitate with chloride ions, the ionic equation Ag+(aq)+Clβˆ’(aq)β†’AgCl(s)\text{Ag}^+(aq) + \text{Cl}^-(aq) \rightarrow \text{AgCl}(s) shows just the ions that react, with state symbols making clear that a solid forms from two dissolved ions. Correct formulae and state symbols are essential here.

Try this

Q1. Write the formula of magnesium nitrate, given Mg2+\text{Mg}^{2+} and NO3βˆ’\text{NO}_3^-. [2 marks]

  • Cue. One Mg2+\text{Mg}^{2+} needs two NO3βˆ’\text{NO}_3^-, so the formula is Mg(NO3)2\text{Mg(NO}_3)_2 (brackets around the nitrate).

Q2. Balance: Fe+O2β†’Fe2O3\text{Fe} + \text{O}_2 \rightarrow \text{Fe}_2\text{O}_3. [2 marks]

  • Cue. 4Fe+3O2β†’2Fe2O34\text{Fe} + 3\text{O}_2 \rightarrow 2\text{Fe}_2\text{O}_3 (iron 4=44 = 4, oxygen 6=66 = 6).

Q3. State what state symbol is used for a substance dissolved in water, and give an example. [1 mark]

  • Cue. (aq)(aq), aqueous; for example NaCl(aq)\text{NaCl}(aq) for salt dissolved in water.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original5 marks(a) Write the formula of aluminium oxide, given the ions Al3+\text{Al}^{3+} and O2βˆ’\text{O}^{2-}. (b) Balance the equation for the reaction of aluminium with oxygen: Al+O2β†’Al2O3\text{Al} + \text{O}_2 \rightarrow \text{Al}_2\text{O}_3. (c) Add state symbols, given all species are solid except oxygen.
Show worked answer β†’

(a) Balance the charges: the lowest common multiple of 33 and 22 is 66, needing two Al3+\text{Al}^{3+} (+6+6) and three O2βˆ’\text{O}^{2-} (βˆ’6-6). The formula is Al2O3\text{Al}_2\text{O}_3.

(b) Balance: 4Al+3O2β†’2Al2O34\text{Al} + 3\text{O}_2 \rightarrow 2\text{Al}_2\text{O}_3. Check: aluminium 4=2Γ—24 = 2 \times 2; oxygen 3Γ—2=6=2Γ—33 \times 2 = 6 = 2 \times 3.

(c) 4Al(s)+3O2(g)β†’2Al2O3(s)4\text{Al}(s) + 3\text{O}_2(g) \rightarrow 2\text{Al}_2\text{O}_3(s).

Markers reward the formula from charge balancing, a correctly balanced equation with whole-number coefficients, and the right state symbols.

Original3 marksBalance the following equation and explain what balancing achieves: C3H8+O2β†’CO2+H2O\text{C}_3\text{H}_8 + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} (the combustion of propane).
Show worked answer β†’

Balance carbon first (3CO23\text{CO}_2), then hydrogen (4H2O4\text{H}_2\text{O}), then oxygen (right-hand side has 6+4=106 + 4 = 10 oxygen atoms, so 5O25\text{O}_2 on the left):

C3H8+5O2β†’3CO2+4H2O\text{C}_3\text{H}_8 + 5\text{O}_2 \rightarrow 3\text{CO}_2 + 4\text{H}_2\text{O}.

Balancing ensures the same number of atoms of each element on both sides, because atoms are neither created nor destroyed in a chemical reaction (conservation of mass).

Markers reward the correct coefficients and the statement that balancing conserves atoms (mass) because none are created or destroyed.

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