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How do we measure how likely an event is, and how do we calculate the probability of a single event?

Find the probability of a single event as a fraction, decimal or percentage, and use the fact that probabilities sum to one

A focused answer to the N(A)-Level Mathematics outcome on probability. The probability scale, equally likely outcomes, calculating probability as favourable over total, and the complement rule.

Generated by Claude Opus 4.88 min answer

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  1. What this dot point is asking
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What this dot point is asking

SEAB wants you to measure how likely a single event is, expressing the probability as a fraction, decimal or percentage, and to use the fact that the probabilities of all outcomes add to 11. Probability is about counting favourable outcomes against all possible outcomes, so careful counting is the main skill.

The answer

The probability scale

Probability measures how likely something is, on a scale from 00 to 11:

  • A probability of 00 means the event is impossible.
  • A probability of 11 means the event is certain.
  • A probability of 12\dfrac{1}{2} means it is as likely as not.

Probabilities can be written as fractions, decimals or percentages: 12\dfrac{1}{2}, 0.50.5 and 50%50\% all describe the same chance.

Equally likely outcomes

When all outcomes are equally likely (a fair die, a well-shuffled pack), the probability of an event is:

probability=number of favourable outcomestotal number of outcomes\text{probability} = \frac{\text{number of favourable outcomes}}{\text{total number of outcomes}}

For a fair die, the probability of rolling a 33 is 16\dfrac{1}{6}, because one face out of six is favourable.

Counting outcomes carefully

The key step is counting correctly. List the favourable outcomes and the total outcomes, then form the fraction. For "an even number on a die", the favourable outcomes are 2,4,62, 4, 6 (three of them), so the probability is 36=12\dfrac{3}{6} = \dfrac{1}{2}.

The complement rule

The outcomes of an event and its opposite (its complement) together cover everything, so their probabilities add to 11:

P(not A)=1P(A)\text{P(not A)} = 1 - \text{P(A)}

If the probability of rain is 0.30.3, the probability of no rain is 10.3=0.71 - 0.3 = 0.7. This is often the quickest way to find a "not" probability.

Simplifying the answer

Give probabilities as simplified fractions unless told otherwise, for example 48\dfrac{4}{8} written as 12\dfrac{1}{2}. A decimal or percentage is also acceptable when the question allows.

Examples in context

Example 1. A spinner. A spinner divided into 88 equal sectors, 33 of them red, gives a probability of red of 38\dfrac{3}{8}. Equal sectors make the outcomes equally likely, so the count of red sectors over the total sectors is the probability.

Example 2. Weather forecasts. When a forecast says there is a 70%70\% chance of rain, the chance of no rain is 100%70%=30%100\% - 70\% = 30\%. The complement rule turns one stated probability into its opposite instantly, which is how "not" probabilities usually arise in real life.

Try this

  • Cue. A fair coin is tossed. The probability of heads is 12\dfrac{1}{2}, since one of two equally likely outcomes is favourable.
  • Cue. A bag has 77 white and 33 black counters. The probability of black is 310\dfrac{3}{10}.
  • Cue. If P(win)=0.4\text{P(win)} = 0.4, then P(not win)=10.4=0.6\text{P(not win)} = 1 - 0.4 = 0.6.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksA bag contains 55 red balls, 33 blue balls and 22 green balls. One ball is taken at random. Find the probability that it is (a) blue and (b) not green.
Show worked answer →

The total number of balls is 5+3+2=105 + 3 + 2 = 10.

(a) Probability of blue =number of bluetotal=310= \dfrac{\text{number of blue}}{\text{total}} = \dfrac{3}{10}.

(b) Probability of green =210=15= \dfrac{2}{10} = \dfrac{1}{5}, so probability of not green =115=45= 1 - \dfrac{1}{5} = \dfrac{4}{5}.

What markers reward: the probability as favourable outcomes over total outcomes, simplifying where possible, and using the complement rule (11 minus the probability) for "not green". Counting the total correctly is the essential first step.

Original2 marksA fair six-sided die is rolled once. Find the probability of rolling a number greater than 44.
Show worked answer →

The outcomes greater than 44 are 55 and 66, so there are 22 favourable outcomes.

There are 66 equally likely outcomes in total.

Probability =26=13= \dfrac{2}{6} = \dfrac{1}{3}.

What markers reward: listing the favourable outcomes (55 and 66), using 66 as the total, and simplifying the fraction. Miscounting which numbers are "greater than 44" (including 44 by mistake) is the usual error.

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