How do we calculate percentages, percentage change, and everyday money problems such as discounts and simple interest?
Find a percentage of a quantity, express one quantity as a percentage of another, calculate percentage change, and solve money problems including discount, profit and simple interest
A focused answer to the N(A)-Level Mathematics outcome on percentage. Finding a percentage, percentage change, and money problems including discount, profit and loss, and simple interest.
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What this dot point is asking
SEAB wants you to find a percentage of a quantity, express one quantity as a percentage of another, calculate percentage increases and decreases, and apply these to money problems such as discounts, profit and loss, and simple interest. Percentages are everywhere in real life, so this is one of the most useful topics in the syllabus.
The answer
What percentage means
"Per cent" means "per hundred", so means . To use a percentage in a calculation, convert it to a fraction or a decimal first.
Finding a percentage of a quantity
Multiply the quantity by the percentage written as a fraction or decimal:
Expressing one quantity as a percentage of another
Write the two quantities as a fraction, then multiply by . For example, a student who scores out of achieves:
Percentage change
Percentage change compares the change with the original amount:
If a price rises from \40\, the change is \10\dfrac{10}{40} \times 100 = 25%$.
Money problems
- Discount. A reduction in price. New price equals original minus discount.
- Profit and loss. Profit is selling price minus cost price; a loss is a negative profit. Profit percentage is usually based on the cost price.
- Simple interest. Interest paid on the original amount (the principal) only. For each year the interest is the same, so total interest equals the one-year interest multiplied by the number of years.
Examples in context
Example 1. A restaurant service charge. A meal costs \6010%\dfrac{10}{100} \times 60 = \, so the total bill is \66110%\ in one step, which is a handy shortcut for increases.
Example 2. Comparing two test scores. A student scores out of in one test and out of in another. As percentages these are and , so the performances are equal even though the raw marks differ. Converting to percentages makes scores from different totals comparable.
Try this
- Cue. Find of \120\dfrac{15}{100} \times 120 = \.
- Cue. A price falls from \50\. The change is \5\dfrac{5}{50} \times 100 = 10%$.
- Cue. Find the simple interest on \8005%2\, so two years give \80$.
Exam-style practice questions
Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.
Original3 marksA jacket costs \8025\%$. Find (a) the discount and (b) the sale price.Show worked answer →
(a) The discount is of \80$:
\dfrac{25}{100} \times 80 = \20$.
(b) The sale price is the original minus the discount:
\80 - \20 = \60$.
What markers reward: converting the percentage to a fraction or decimal, multiplying by the original price, and subtracting to find the sale price. An equally valid method is to find of \80\.
Original3 marksA boy puts \5004\%3$ years and the total amount in the account.Show worked answer →
Interest for one year is of \500\dfrac{4}{100} \times 500 = \.
For years: \20 \times 3 = \.
Total amount: \500 + \60 = \560$.
What markers reward: the simple interest method (interest for one year, then multiply by the number of years), and adding the interest to the original amount for the total. Multiplying the principal by the rate and the time in any equivalent order is fine.
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