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How do we calculate percentages, percentage change, and everyday money problems such as discounts and simple interest?

Find a percentage of a quantity, express one quantity as a percentage of another, calculate percentage change, and solve money problems including discount, profit and simple interest

A focused answer to the N(A)-Level Mathematics outcome on percentage. Finding a percentage, percentage change, and money problems including discount, profit and loss, and simple interest.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to find a percentage of a quantity, express one quantity as a percentage of another, calculate percentage increases and decreases, and apply these to money problems such as discounts, profit and loss, and simple interest. Percentages are everywhere in real life, so this is one of the most useful topics in the syllabus.

The answer

What percentage means

"Per cent" means "per hundred", so 25%25\% means 25100=0.25\dfrac{25}{100} = 0.25. To use a percentage in a calculation, convert it to a fraction or a decimal first.

Finding a percentage of a quantity

Multiply the quantity by the percentage written as a fraction or decimal:

30% of $60=30100×60=$18.30\% \text{ of } \$60 = \frac{30}{100} \times 60 = \$18.

Expressing one quantity as a percentage of another

Write the two quantities as a fraction, then multiply by 100100. For example, a student who scores 1818 out of 2020 achieves:

1820×100=90%.\frac{18}{20} \times 100 = 90\%.

Percentage change

Percentage change compares the change with the original amount:

percentage change=changeoriginal×100\text{percentage change} = \frac{\text{change}}{\text{original}} \times 100

If a price rises from \40to to \5050, the change is \10andthepercentageincreaseis and the percentage increase is \dfrac{10}{40} \times 100 = 25%$.

Money problems

  • Discount. A reduction in price. New price equals original minus discount.
  • Profit and loss. Profit is selling price minus cost price; a loss is a negative profit. Profit percentage is usually based on the cost price.
  • Simple interest. Interest paid on the original amount (the principal) only. For each year the interest is the same, so total interest equals the one-year interest multiplied by the number of years.

Examples in context

Example 1. A restaurant service charge. A meal costs \60anda and a 10%servicechargeisadded.Thechargeis service charge is added. The charge is \dfrac{10}{100} \times 60 = \66, so the total bill is \66.Thesameanswercomesfromfinding. The same answer comes from finding 110%of of \6060 in one step, which is a handy shortcut for increases.

Example 2. Comparing two test scores. A student scores 2424 out of 4040 in one test and 3030 out of 5050 in another. As percentages these are 60%60\% and 60%60\%, so the performances are equal even though the raw marks differ. Converting to percentages makes scores from different totals comparable.

Try this

  • Cue. Find 15%15\% of \120.Compute. Compute \dfrac{15}{100} \times 120 = \1818.
  • Cue. A price falls from \50to to \4545. The change is \5,sothepercentagedecreaseis, so the percentage decrease is \dfrac{5}{50} \times 100 = 10%$.
  • Cue. Find the simple interest on \800at at 5%peryearfor per year for 2years.Oneyearis years. One year is \4040, so two years give \80$.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksA jacket costs \80.Inasaleitisreducedby. In a sale it is reduced by 25\%$. Find (a) the discount and (b) the sale price.
Show worked answer →

(a) The discount is 25%25\% of \80$:

\dfrac{25}{100} \times 80 = \20$.

(b) The sale price is the original minus the discount:

\80 - \20 = \60$.

What markers reward: converting the percentage to a fraction or decimal, multiplying by the original price, and subtracting to find the sale price. An equally valid method is to find 75%75\% of \80directly,whichalsogives directly, which also gives \6060.

Original3 marksA boy puts \500intoasavingsaccountthatpayssimpleinterestat into a savings account that pays simple interest at 4\%peryear.Findtheinterestearnedafter per year. Find the interest earned after 3$ years and the total amount in the account.
Show worked answer →

Interest for one year is 4%4\% of \500:: \dfrac{4}{100} \times 500 = \2020.

For 33 years: \20 \times 3 = \6060.

Total amount: \500 + \60 = \560$.

What markers reward: the simple interest method (interest for one year, then multiply by the number of years), and adding the interest to the original amount for the total. Multiplying the principal by the rate and the time in any equivalent order is fine.

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