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What do the mean, median and mode each measure, and how do we calculate them?

Calculate the mean, median and mode of a set of data, find the range, and choose an appropriate average

A focused answer to the N(A)-Level Mathematics outcome on averages. The mean, median and mode, the range as a measure of spread, and when each average best represents the data.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

SEAB wants you to calculate the three averages - mean, median and mode - and the range of a data set, and to comment on which average best represents the data. Each average summarises a data set with a single number, but they measure slightly different things, so knowing the difference matters.

The answer

The mean

The mean is the everyday "average": add up all the values and divide by how many there are.

mean=sum of all valuesnumber of values\text{mean} = \frac{\text{sum of all values}}{\text{number of values}}

For 3,5,73, 5, 7 the mean is 153=5\dfrac{15}{3} = 5. The mean uses every value, so it is affected by very large or very small ones.

The median

The median is the middle value when the data is arranged in order. If there is an even number of values, the median is the mean of the two middle ones.

For 2,4,6,8,102, 4, 6, 8, 10 the median is 66. The median is not pulled around by extreme values, so it can be a fairer "typical" value.

The mode

The mode is the value that appears most often. A data set can have one mode, more than one mode, or no mode if all values appear equally. The mode is the only average that works for non-numerical data, such as the most common colour.

The range

The range measures spread, not average:

range=largest valuesmallest value\text{range} = \text{largest value} - \text{smallest value}

A small range means the data is close together; a large range means it is spread out.

Averages from a frequency table

When data is given in a frequency table, the same ideas apply. The mode is the value with the highest frequency. The median is found by counting through the frequencies to the middle position. The mean is the total of (value times frequency) divided by the total frequency. Reading averages from a table is common once data has been organised.

Choosing an average

The mean is best when the data is fairly even. The median is better when there are a few extreme values that would distort the mean. The mode is best for the most popular category, and is the only average that works for non-numerical data such as favourite colour. Questions often ask you to justify the choice, so be ready to give a short reason.

Examples in context

Example 1. Comparing test scores. Two classes can have the same mean score but very different ranges. The class with the smaller range had more consistent results, while the larger range shows a wider spread of ability. Reporting the mean and the range together gives a fuller picture than the mean alone.

Example 2. The effect of an outlier. In the salaries 20,22,24,26,20020, 22, 24, 26, 200 (in thousands), the single large value pulls the mean up to 58.458.4, which represents nobody well. The median of 2424 is a far more typical figure. This is exactly when the median is preferred over the mean.

Try this

  • Cue. Find the mean of 2,4,6,82, 4, 6, 8. Sum is 2020, count is 44, so mean =5= 5.
  • Cue. Find the median of 3,9,1,7,53, 9, 1, 7, 5. Order to 1,3,5,7,91, 3, 5, 7, 9; the middle is 55.
  • Cue. Find the mode and range of 6,2,6,9,6,26, 2, 6, 9, 6, 2. The mode is 66 and the range is 92=79 - 2 = 7.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marksFind the mean, median, mode and range of the data set: 4,7,7,2,104, 7, 7, 2, 10.
Show worked answer →

Mean: add the values and divide by how many there are. Sum =4+7+7+2+10=30= 4 + 7 + 7 + 2 + 10 = 30, and there are 55 values, so mean =305=6= \dfrac{30}{5} = 6.

Median: order the data 2,4,7,7,102, 4, 7, 7, 10 and take the middle value, which is 77.

Mode: the most common value is 77 (it appears twice).

Range: largest minus smallest =102=8= 10 - 2 = 8.

What markers reward: the correct method for each measure - sum over count for the mean, the middle of the ordered list for the median, the most frequent for the mode, and largest minus smallest for the range. Forgetting to order the data before finding the median is the common slip.

Original3 marksThe mean of four numbers is 99. Three of the numbers are 77, 88 and 1212. Find the fourth number.
Show worked answer →

If the mean of four numbers is 99, their total must be 4×9=364 \times 9 = 36.

The three known numbers add to 7+8+12=277 + 8 + 12 = 27.

So the fourth number is 3627=936 - 27 = 9.

What markers reward: using the mean to find the total (mean times count), subtracting the known values, and the correct fourth number. Working backward from the mean to the total is the key idea.

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