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How do we compare quantities with ratio, work with rates, and solve direct proportion problems?

Express and simplify ratios, divide a quantity in a given ratio, work with rates, and solve direct proportion problems

A focused answer to the N(A)-Level Mathematics outcome on ratio. Simplifying ratios, sharing in a ratio, working with rates such as speed, and solving direct proportion problems by the unitary method.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to write and simplify ratios, divide a quantity in a given ratio, work with rates such as speed or price per item, and solve direct proportion problems where two quantities increase together. These ideas appear in money, measurement and travel-graph questions, so they are worth mastering early.

The answer

What a ratio is

A ratio compares two or more quantities of the same kind. The ratio 3:23 : 2 means that for every 33 of the first quantity there are 22 of the second. Ratios have no units because the units cancel.

Simplifying a ratio

Divide every part by their common factor, just like simplifying a fraction. For example, 12:812 : 8 divides by 44 to give 3:23 : 2. To compare unlike units, first convert to the same unit: 1 m:50 cm1\ \text{m} : 50\ \text{cm} becomes 100 cm:50 cm=2:1100\ \text{cm} : 50\ \text{cm} = 2 : 1.

Sharing in a ratio

To divide a quantity in a ratio:

  1. Add the parts to find the total number of parts.
  2. Divide the quantity by the total to find the value of one part.
  3. Multiply by each share.

For example, to share \300intheratio in the ratio 2 : 3 : 1:thereare: there are 6parts,onepartis parts, one part is \5050, and the shares are \100,, \150150 and \50$.

Rates

A rate compares two quantities of different kinds, such as distance and time. Speed is the most common rate:

speed=distancetime\text{speed} = \frac{\text{distance}}{\text{time}}

Other rates include price per kilogram and words typed per minute. A rate always carries units, for example km/h or \$/kg.

Direct proportion and the unitary method

Two quantities are in direct proportion when one is a constant multiple of the other: double one and the other doubles. The fastest way to solve such problems is the unitary method - find the value of one unit first, then scale up.

For example, if 44 pens cost \6,thenonepencosts, then one pen costs \6 \div 4 = \1.50,so, so 10penscost pens cost 10 \times \1.50 = \15$.

Examples in context

Example 1. A recipe scaled up. A recipe for 44 people needs 200 g200\ \text{g} of flour. For 66 people, find one person's share first: 200÷4=50 g200 \div 4 = 50\ \text{g} each, so 6×50=300 g6 \times 50 = 300\ \text{g}. This unitary method works for any number of people and is the same idea as direct proportion.

Example 2. Comparing value. A 500 g500\ \text{g} pack of rice costs \2.00anda and a 2\ \text{kg}packcosts pack costs \7.207.20. Compare the rate per kilogram: the small pack is \4.00/kgandthelargepackis/kg and the large pack is \3.603.60/kg, so the large pack is better value. Turning each price into a rate makes the comparison fair.

Try this

  • Cue. Simplify the ratio 18:2418 : 24. Divide both by 66 to get 3:43 : 4.
  • Cue. Share \450intheratio in the ratio 4 : 5.Thereare. There are 9parts,onepartis parts, one part is \5050, so the shares are \200and and \250250.
  • Cue. If 55 identical books cost \40,findthecostof, find the cost of 8books.Onebookis books. One book is \88, so 88 books cost \64$.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksA sum of \200issharedbetweenAishahandBenintheratio is shared between Aishah and Ben in the ratio 3 : 2$. How much does each person receive?
Show worked answer →

Add the parts of the ratio: 3+2=53 + 2 = 5 parts.

Find the value of one part: \200 \div 5 = \4040.

Aishah gets 33 parts: 3 \times \40 = \120120.

Ben gets 22 parts: 2 \times \40 = \8080.

Check: \120 + \80 = \200$.

What markers reward: adding the parts, finding the value of one part, and a correct share for each person. A quick check that the shares add back to the total confirms the answer.

Original3 marksA car travels 150 km150\ \text{km} in 22 hours at a steady speed. (a) Find its average speed. (b) How far would it travel in 55 hours at the same speed?
Show worked answer →

(a) Average speed is distance divided by time: 1502=75 km/h\dfrac{150}{2} = 75\ \text{km/h}.

(b) At 75 km/h75\ \text{km/h} for 55 hours: 75×5=375 km75 \times 5 = 375\ \text{km}.

What markers reward: the correct rate formula (speed equals distance over time), correct units of km/h, and using the rate to scale up to the new time. Stating the unit on the speed is part of the mark.

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