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SingaporeChemistrySyllabus dot point

How do we write the formula of a compound and balance a chemical equation so that no atoms are lost?

Write formulae of common compounds from ion charges, write word equations, and balance symbol equations including state symbols

A focused answer to the N(A) Chemistry outcome on formulae and equations. Building formulae from ion charges, writing word equations, and balancing symbol equations with state symbols so atoms are conserved.

Generated by Claude Opus 4.89 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

The syllabus wants you to write the formula of a common compound from the charges on its ions, to write a word equation for a reaction, and to write and balance a symbol equation with state symbols. Balancing matters because atoms are never created or destroyed in a reaction, so each element must have the same number of atoms on both sides. These skills feed directly into the mole calculations later in this module.

The answer

Writing a formula from ion charges

To write the formula of an ionic compound, balance the charges so the compound is neutral:

  • Find the charge on each ion (Group I is 1+1+, Group II is 2+2+, Group VII is 1βˆ’1-, and so on, with common ions such as OHβˆ’\text{OH}^{-}, NO3βˆ’\text{NO}_3^{-}, SO42βˆ’\text{SO}_4^{2-}, CO32βˆ’\text{CO}_3^{2-} learnt by heart).
  • Combine them so the total positive charge equals the total negative charge.

For example, Ca2+\text{Ca}^{2+} with Clβˆ’\text{Cl}^{-} needs two chlorides, giving CaCl2\text{CaCl}_2.

Brackets for groups of atoms

When more than one of a group ion is needed, put it in brackets with a subscript. For example, calcium hydroxide is Ca(OH)2\text{Ca(OH)}_2, because one Ca2+\text{Ca}^{2+} needs two OHβˆ’\text{OH}^{-} ions.

Word equations

A word equation names the reactants and products with an arrow:

reactants→products\text{reactants} \rightarrow \text{products}

For example: zinc + hydrochloric acid β†’\rightarrow zinc chloride + hydrogen.

Balancing a symbol equation

A symbol equation uses formulae. To balance it, put big numbers (coefficients) in front of formulae until each element has equal atoms on both sides. Never change a formula; only change the numbers in front. Then add state symbols:

  • (s)(s) solid, (l)(l) liquid, (g)(g) gas, (aq)(aq) dissolved in water (aqueous).

Examples in context

Example 1. Reading a recipe for a reaction. A balanced equation is like a recipe: 2H2+O2β†’2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} tells you two molecules of hydrogen react with one of oxygen. The numbers are the ratio you will use in mole calculations, so a correctly balanced equation is the starting point for working out masses.

Example 2. State symbols showing a precipitate. When two solutions react to form an insoluble solid, the state symbols make it clear: Ag+(aq)+Clβˆ’(aq)β†’AgCl(s)\text{Ag}^{+}(aq) + \text{Cl}^{-}(aq) \rightarrow \text{AgCl}(s). The (s)(s) shows a precipitate forms, which links directly to the qualitative analysis tests for ions.

Try this

Q1. Write the formula of aluminium oxide, given the ions Al3+\text{Al}^{3+} and O2βˆ’\text{O}^{2-}. [2 marks]

  • Cue. Balance the charges: two Al3+\text{Al}^{3+} (total 6+6+) with three O2βˆ’\text{O}^{2-} (total 6βˆ’6-) gives Al2O3\text{Al}_2\text{O}_3.

Q2. Balance the equation Fe+O2β†’Fe2O3\text{Fe} + \text{O}_2 \rightarrow \text{Fe}_2\text{O}_3. [2 marks]

  • Cue. 4Fe+3O2β†’2Fe2O34\text{Fe} + 3\text{O}_2 \rightarrow 2\text{Fe}_2\text{O}_3, giving 44 Fe and 66 O atoms on each side.

Q3. Write the balanced symbol equation, with state symbols, for zinc reacting with hydrochloric acid to give zinc chloride solution and hydrogen gas. [2 marks]

  • Cue. Zn(s)+2HCl(aq)β†’ZnCl2(aq)+H2(g)\text{Zn}(s) + 2\text{HCl}(aq) \rightarrow \text{ZnCl}_2(aq) + \text{H}_2(g).

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marksMagnesium burns in oxygen to form magnesium oxide. (a) Write the word equation. (b) Write the balanced symbol equation with state symbols.
Show worked answer β†’

(a) Word equation: magnesium + oxygen β†’\rightarrow magnesium oxide.

(b) Magnesium oxide is MgO\text{MgO} and oxygen is O2\text{O}_2. Balancing gives:

2Mg(s)+O2(g)β†’2MgO(s)2\text{Mg}(s) + \text{O}_2(g) \rightarrow 2\text{MgO}(s)

There are now 22 Mg and 22 O atoms on each side.

What markers reward: the correct word equation, the formulae MgO\text{MgO} and O2\text{O}_2, the balancing numbers 2,1,22, 1, 2, and correct state symbols.

Original4 marksBalance the following equations. (a) H2+O2β†’H2O\text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O}. (b) Na+Cl2β†’NaCl\text{Na} + \text{Cl}_2 \rightarrow \text{NaCl}.
Show worked answer β†’

(a) Balance oxygen and hydrogen:

2H2+O2β†’2H2O2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}

Each side has 44 H and 22 O atoms.

(b) Balance chlorine and sodium:

2Na+Cl2β†’2NaCl2\text{Na} + \text{Cl}_2 \rightarrow 2\text{NaCl}

Each side has 22 Na and 22 Cl atoms.

What markers reward: equal atoms of each element on both sides, the correct big numbers in front, and not changing any chemical formula.

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