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SingaporeMathsSyllabus dot point

How do we find the area and perimeter of standard plane figures and composite shapes?

Calculate the perimeter and area of triangles, quadrilaterals and circles, and of composite plane figures

A focused answer to the O-Level E-Maths outcome on area and perimeter. The standard area formulas for triangles, parallelograms, trapeziums and circles, perimeter and circumference, and composite figures.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

SEAB wants you to find the perimeter and area of standard plane figures, triangles, rectangles, parallelograms, trapeziums and circles, and to handle composite shapes made by combining or subtracting these. Reliable use of the standard formulas, with correct units, is the foundation of the mensuration strand.

The answer

Perimeter

The perimeter is the total distance around a shape, found by adding all the outer sides. For a circle the perimeter is called the circumference:

C=2πr=πdC = 2\pi r = \pi d

where rr is the radius and dd the diameter.

Areas of standard shapes

The key area formulas are:

  • rectangle: length×width\text{length} \times \text{width},
  • triangle: 12×base×height\dfrac{1}{2} \times \text{base} \times \text{height},
  • parallelogram: base×height\text{base} \times \text{height},
  • trapezium: 12(a+b)h\dfrac{1}{2}(a + b)h, where aa and bb are the parallel sides,
  • circle: πr2\pi r^2.

The height in a triangle or parallelogram is the perpendicular height, not a slanted side.

Composite figures

A composite figure is built from standard shapes. Find its area by splitting it into pieces and adding, or by taking a large shape and subtracting a removed piece. The perimeter of a composite shape follows the actual outer boundary, which may include parts of circles.

Units

Area is measured in square units (cm2\text{cm}^2, m2\text{m}^2) and perimeter in linear units (cm\text{cm}, m\text{m}). Convert all lengths to the same unit before calculating, and state the correct unit with the answer.

Examples in context

Example 1. Flooring a room. Tiling an L-shaped room means splitting the floor into two rectangles, finding each area, and adding them to get the total area of tiling needed. Composite-area thinking is exactly what tradespeople do.

Example 2. A running track. The perimeter of a track with two straight sides and two semicircular ends combines straight lengths with the circumference of a full circle (the two semicircles). The total distance is what a runner covers in one lap.

Try this

Q1. Find the area of a triangle with base 12 cm12\ \text{cm} and perpendicular height 5 cm5\ \text{cm}. [1 mark]

  • Cue. 12×12×5=30 cm2\dfrac{1}{2} \times 12 \times 5 = 30\ \text{cm}^2.

Q2. Find the circumference of a circle of diameter 10 cm10\ \text{cm}, taking π=3.142\pi = 3.142. [2 marks]

  • Cue. C=πd=3.142×10=31.42 cmC = \pi d = 3.142 \times 10 = 31.42\ \text{cm}.

Q3. Find the area of a trapezium with parallel sides 6 cm6\ \text{cm} and 10 cm10\ \text{cm} and height 4 cm4\ \text{cm}. [2 marks]

  • Cue. 12(6+10)×4=12×16×4=32 cm2\dfrac{1}{2}(6 + 10) \times 4 = \dfrac{1}{2} \times 16 \times 4 = 32\ \text{cm}^2.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksA circle has radius 7 cm7\ \text{cm}. Taking π=3.142\pi = 3.142, find (a) its circumference and (b) its area, each to 1 decimal place.
Show worked answer →

(a) Circumference =2πr=2×3.142×7=43.988= 2\pi r = 2 \times 3.142 \times 7 = 43.988, which is 44.0 cm44.0\ \text{cm} to 1 decimal place.

(b) Area =πr2=3.142×72=3.142×49=153.958= \pi r^2 = 3.142 \times 7^2 = 3.142 \times 49 = 153.958, which is 154.0 cm2154.0\ \text{cm}^2 to 1 decimal place.

Markers reward the circumference formula 2πr2\pi r, the area formula πr2\pi r^2, correct substitution and rounding.

Original4 marksA trapezium has parallel sides 8 cm8\ \text{cm} and 14 cm14\ \text{cm} and a perpendicular height of 5 cm5\ \text{cm}. (a) Find its area. (b) A square has the same area; find the length of its side, to 2 decimal places.
Show worked answer →

(a) Area of a trapezium =12(a+b)h=12(8+14)×5=12×22×5=55 cm2= \dfrac{1}{2}(a + b)h = \dfrac{1}{2}(8 + 14) \times 5 = \dfrac{1}{2} \times 22 \times 5 = 55\ \text{cm}^2.

(b) A square of area 55 cm255\ \text{cm}^2 has side 55=7.416\sqrt{55} = 7.416\ldots, which is 7.42 cm7.42\ \text{cm} to 2 decimal places.

Markers reward the trapezium area formula, the value 55 cm255\ \text{cm}^2, and the square root for the square's side.

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