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How do we solve linear inequalities and represent the solution set?

Solve linear inequalities in one variable, represent solutions on a number line, and find integer values that satisfy an inequality

A focused answer to the O-Level E-Maths outcome on linear inequalities. Solving inequalities, the rule for reversing the sign when multiplying or dividing by a negative, number-line representation, and listing integer solutions.

Generated by Claude Opus 4.87 min answer

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to solve linear inequalities in one variable, show the solution on a number line, and list integer values that satisfy an inequality or a pair of bounds. The methods mirror solving equations, with one crucial extra rule about negatives.

The answer

Inequality signs

The four signs are less than <<, greater than >>, less than or equal to \le, and greater than or equal to \ge. A strict sign (<< or >>) excludes the boundary value; an inclusive sign (\le or \ge) includes it.

Solving like an equation, with one exception

Solve an inequality almost exactly as you solve an equation: add, subtract, expand and collect terms freely. The one exception is that multiplying or dividing both sides by a negative number reverses the direction of the inequality. So from 3x<12-3x < 12 you divide by 3-3 to get x>4x > -4, with the sign flipped.

Representing the solution on a number line

Draw the solution as a shaded region on a number line. Use an open (hollow) circle at a boundary that is excluded by a strict inequality, and a closed (filled) circle at a boundary included by an inclusive inequality, then shade in the direction of the solution.

Double inequalities and integer solutions

A double inequality such as 3x<5-3 \le x < 5 bounds the variable on both sides; operate on all three parts at once. To list integer solutions, identify the smallest and largest integers inside the range, taking care over which boundary is included.

Examples in context

Example 1. A budget constraint. If items cost 44 dollars each and you have at most 3030 dollars, the number bought nn satisfies 4n304n \le 30, so n7.5n \le 7.5, meaning at most 77 items since nn must be a whole number. Inequalities model limits and budgets naturally.

Example 2. Acceptable measurements. A component is acceptable if its length LL lies within tolerance, say 49.5L50.549.5 \le L \le 50.5. This double inequality describes the allowed range, and any reading outside it fails the check.

Try this

Q1. Solve 2x5<92x - 5 < 9. [2 marks]

  • Cue. Add 55: 2x<142x < 14, then divide by 22: x<7x < 7.

Q2. Solve 4x20-4x \ge 20. [2 marks]

  • Cue. Divide by 4-4 and flip the sign: x5x \le -5.

Q3. List the integers satisfying 2x<3-2 \le x < 3. [2 marks]

  • Cue. Include 2-2, exclude 33: the integers are 2,1,0,1,2-2, -1, 0, 1, 2.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksSolve the inequality 32x113 - 2x \le 11, and represent the solution on a number line.
Show worked answer →

Subtract 33 from both sides: 2x8-2x \le 8.

Divide both sides by 2-2, and because you divide by a negative the inequality sign reverses: x4x \ge -4.

On a number line, draw a solid (filled) circle at 4-4 and shade the line to the right.

Markers reward isolating the xx term, reversing the inequality when dividing by a negative, and a correct number-line diagram with a filled circle.

Original3 marksFind all the integers xx that satisfy 5<2x17-5 < 2x - 1 \le 7.
Show worked answer →

Add 11 throughout: 4<2x8-4 < 2x \le 8.

Divide throughout by 22: 2<x4-2 < x \le 4.

The integers satisfying this are 1,0,1,2,3,4-1, 0, 1, 2, 3, 4.

Markers reward working on all three parts of the double inequality together, the correct range 2<x4-2 < x \le 4, and listing exactly the integers in that range.

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