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SingaporeMathsSyllabus dot point

How do we construct accurate figures and describe the set of points satisfying a condition?

Construct triangles, angle bisectors and perpendicular bisectors with compasses, and describe and draw simple loci

A focused answer to the O-Level E-Maths outcome on constructions and loci. Constructing perpendicular and angle bisectors, the standard loci, and combining conditions to find a region.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to use compasses and a straight edge to construct triangles and bisectors accurately, and to describe and draw loci, the set of all points satisfying a given condition. Loci questions often combine two conditions and ask for the region where both hold.

The answer

Constructing a triangle

Given three sides, draw the base with a ruler, then use compasses set to each of the other two lengths to draw arcs from the two ends; their intersection is the third vertex. Always leave your construction arcs visible, as they show the method and earn marks.

Perpendicular bisector

The perpendicular bisector of a segment ABAB is constructed by opening the compasses to more than half of ABAB and drawing arcs from both AA and BB above and below the line; the line through the two arc intersections is the perpendicular bisector. Every point on it is equidistant from AA and BB.

Angle bisector

To bisect an angle, draw an arc from the vertex crossing both arms, then from those two crossing points draw two more arcs that meet; the line from the vertex through that meeting point bisects the angle. Every point on it is equidistant from the two arms.

Standard loci

  • The locus of points a fixed distance rr from a point is a circle of radius rr.
  • The locus of points equidistant from two points is the perpendicular bisector of the segment joining them.
  • The locus of points equidistant from two lines (or the arms of an angle) is the angle bisector.
  • The locus of points a fixed distance from a line is a pair of parallel lines.

Combining loci

When a point must satisfy two conditions at once, draw each locus and identify the overlap, the region or points common to both. Less than a distance gives the inside of a circle; nearer to one side gives one side of a bisector.

Examples in context

Example 1. Positioning a transmitter. A radio mast that must be equidistant from two towns sits on the perpendicular bisector of the line joining them. Adding a maximum-range condition (a circle) pins it to part of that bisector.

Example 2. Safe zones. A path that must stay at least a set distance from a building edge is bounded by a locus parallel to the edge. Planners use such loci to mark out clearances and safety margins.

Try this

Q1. Describe the locus of points 5 cm5\ \text{cm} from a fixed point PP. [1 mark]

  • Cue. A circle of radius 5 cm5\ \text{cm} centred on PP.

Q2. What construction gives the locus of points equidistant from two intersecting lines? [1 mark]

  • Cue. The angle bisector of the angle between them.

Q3. A point must be within 3 cm3\ \text{cm} of AA and equidistant from AA and BB. Describe the locus. [2 marks]

  • Cue. The part of the perpendicular bisector of ABAB that lies inside the circle of radius 3 cm3\ \text{cm} centred on AA.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksDescribe the locus of points that are exactly 3 cm3\ \text{cm} from a fixed point AA, and the locus of points equidistant from two fixed points AA and BB.
Show worked answer →

The locus of points exactly 3 cm3\ \text{cm} from AA is a circle of radius 3 cm3\ \text{cm} centred on AA.

The locus of points equidistant from AA and BB is the perpendicular bisector of the line segment ABAB, the straight line that cuts ABAB in half at a right angle.

Markers reward the circle for the fixed-distance locus and the perpendicular bisector for the equidistant locus.

Original4 marksA point PP lies inside a rectangular garden so that it is less than 4 m4\ \text{m} from corner AA and nearer to side ABAB than to side ADAD. Describe the two loci involved and the region where PP can lie.
Show worked answer →

The first condition, less than 4 m4\ \text{m} from AA, is the region inside a circle of radius 4 m4\ \text{m} centred on AA.

The second condition, nearer to ABAB than to ADAD, is the region on the ABAB side of the angle bisector of angle DABDAB (the bisector is equidistant from the two sides).

The valid region for PP is where both hold: inside the circle and on the ABAB side of the bisector.

Markers reward the circle region for the distance condition, the angle bisector for the equidistant-from-two-sides condition, and the overlap as the final region.

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