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How do turning forces balance, and how does a force spread over an area create pressure?

Define the moment of a force and apply the principle of moments, and define pressure and apply p = F/A including pressure in liquids

A focused answer to the O-Level Combined Science outcome on moments and pressure. The moment of a force, the principle of moments for a balanced beam, pressure as force per area, and pressure in liquids.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
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  3. Examples in context
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What this dot point is asking

SEAB wants you to define the moment of a force as its turning effect, to apply the principle of moments to a balanced beam, and to define pressure as force per unit area and apply p=F/Ap = F/A, including the way pressure increases with depth in a liquid. The arithmetic is simple multiplication and division; the marks come from the definitions and from choosing the perpendicular distance.

The answer

The moment of a force

A moment is the turning effect of a force about a pivot:

moment=force×perpendicular distance from the pivot\text{moment} = \text{force} \times \text{perpendicular distance from the pivot}

The unit is the newton metre (N m\text{N m}). A larger force or a longer distance gives a bigger turning effect, which is why a long spanner loosens a tight nut more easily than a short one.

The principle of moments

When an object is balanced (in equilibrium) and not turning, the total clockwise moment about any pivot equals the total anticlockwise moment:

sum of clockwise moments=sum of anticlockwise moments\text{sum of clockwise moments} = \text{sum of anticlockwise moments}

This lets you find an unknown force or distance on a balanced beam such as a seesaw or a ruler balanced on a pivot.

Pressure

Pressure is the force acting per unit area:

p=FAp = \frac{F}{A}

The unit is the pascal (Pa\text{Pa}), where 1 Pa=1 N/m21\ \text{Pa} = 1\ \text{N/m}^2. The same force gives a higher pressure over a smaller area, which is why a sharp knife cuts well and a drawing pin pushes in easily at its point.

Pressure in liquids

In a liquid the pressure increases with depth, because a deeper point has more liquid weighing down on it. The pressure due to a column of liquid is:

p=ρghp = \rho g h

where ρ\rho is the density of the liquid, gg the gravitational field strength and hh the depth. Liquid pressure acts equally in all directions at a given depth.

Examples in context

Example 1. A wheelbarrow. The wheel acts as the pivot. By placing the load close to the wheel, its moment is small, so a modest lifting force at the far end of the long handles balances it. The handles give a large distance and therefore a large moment for little effort.

Example 2. Snowshoes and tractor tyres. Spreading weight over a large area lowers the pressure on soft ground, so the wearer or vehicle does not sink. The same weight on a small area, like a stiletto heel, gives a very high pressure that dents soft surfaces.

Try this

Q1. Define the moment of a force. [2 marks]

  • Cue. The moment is the force multiplied by the perpendicular distance from the pivot to the line of action of the force.

Q2. A force of 50 N50\ \text{N} acts on an area of 0.020 m20.020\ \text{m}^2. Find the pressure. [2 marks]

  • Cue. p=FA=500.020=2500 Pap = \dfrac{F}{A} = \dfrac{50}{0.020} = 2500\ \text{Pa}.

Q3. Explain why pressure in a liquid increases with depth. [2 marks]

  • Cue. A deeper point has a greater height of liquid above it, so more weight of liquid pushes down, giving a higher pressure.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marksA uniform beam is pivoted at its centre. A 6.0 N6.0\ \text{N} weight hangs 0.40 m0.40\ \text{m} to the left of the pivot. At what distance to the right must a 4.0 N4.0\ \text{N} weight hang to balance the beam?
Show worked answer →

By the principle of moments, for balance the anticlockwise moment equals the clockwise moment.

Anticlockwise moment =6.0×0.40=2.4 N m= 6.0 \times 0.40 = 2.4\ \text{N m}.

Set this equal to the clockwise moment: 4.0×d=2.44.0 \times d = 2.4, so d=2.44.0=0.60 md = \dfrac{2.4}{4.0} = 0.60\ \text{m}.

Markers reward stating the principle of moments, computing each moment as force times perpendicular distance, and the correct distance 0.60 m0.60\ \text{m}.

Original3 marksA box weighs 240 N240\ \text{N} and its base measures 0.30 m0.30\ \text{m} by 0.20 m0.20\ \text{m}. (a) Calculate the area of the base. (b) Calculate the pressure it exerts on the floor.
Show worked answer →

(a) Area: A=0.30×0.20=0.060 m2A = 0.30 \times 0.20 = 0.060\ \text{m}^2.

(b) Pressure: p=FA=2400.060=4000 Pap = \dfrac{F}{A} = \dfrac{240}{0.060} = 4000\ \text{Pa}.

Markers reward the area calculation, the use of p=F/Ap = F/A, and the unit pascal (Pa\text{Pa}, equal to N/m2\text{N/m}^2).

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