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How do chemists count atoms by weighing, and what does the mole let us calculate?

Define relative atomic mass and the mole, calculate relative formula mass, and find the number of moles from a given mass

A focused N(A)-Level answer on the mole. Relative atomic mass, relative formula mass, and using moles equals mass divided by relative formula mass in simple calculations.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

SEAB wants you to define relative atomic mass and the mole, to calculate the relative formula mass of a compound, and to find the number of moles from a given mass. The central idea is that the mole lets chemists count huge numbers of tiny atoms simply by weighing them.

The answer

Relative atomic mass

Atoms are far too small and light to weigh one at a time, so chemists compare their masses. The relative atomic mass (ArA_r) of an element tells you how heavy its atoms are compared with other atoms. You read these values from the periodic table, for example H=1\text{H} = 1, C=12\text{C} = 12, O=16\text{O} = 16.

The mole

A mole is simply a fixed, very large number of particles, in the same way that a dozen is 1212 of something. The clever part is that one mole of any element has a mass in grams equal to its relative atomic mass. So one mole of carbon weighs 12 g12\ \text{g}, and one mole of oxygen atoms weighs 16 g16\ \text{g}. This lets us count atoms by weighing.

Relative formula mass

The relative formula mass (MrM_r) of a compound is found by adding up the relative atomic masses of all the atoms in its formula. Remember to multiply by the small numbers in the formula:

Mr(CO2)=12+(2×16)=44M_r(\text{CO}_2) = 12 + (2 \times 16) = 44

Finding moles from mass

The link between mass, moles and relative formula mass is:

moles=massrelative formula massn=mMr\text{moles} = \frac{\text{mass}}{\text{relative formula mass}} \qquad n = \frac{m}{M_r}

This can be rearranged to find the mass from a number of moles, or the relative formula mass from mass and moles. A simple way to remember it is to picture the three quantities in a triangle, with mass on top and moles and MrM_r below: cover the one you want and the triangle shows whether to divide or multiply.

Reading a chemical formula

The formula of a compound tells you exactly which atoms it contains and how many of each. The small numbers (subscripts) apply only to the symbol just before them:

  • CO2\text{CO}_2 means one carbon and two oxygen atoms,
  • H2SO4\text{H}_2\text{SO}_4 means two hydrogen, one sulfur and four oxygen atoms,
  • CaCl2\text{CaCl}_2 means one calcium and two chlorine atoms.

Getting these counts right is the first step in working out a relative formula mass, so always read the formula carefully before you add the masses.

Examples in context

Example 1. Scaling up a recipe. A reaction equation works in moles, just like a recipe works in numbers of eggs. Knowing the moles of each substance lets a factory scale a small lab reaction up to industrial amounts while keeping the proportions correct.

Example 2. Checking a label. A fertiliser bag states it contains a certain mass of a compound. Converting that mass to moles tells a farmer how much of the active element is actually present, because the mole links mass to the number of particles that take part in reactions.

Try this

  • Cue. Find the relative formula mass of NaCl\text{NaCl} (Na=23\text{Na} = 23, Cl=35.5\text{Cl} = 35.5): 23+35.5=58.523 + 35.5 = 58.5.
  • Cue. Find the moles in 8 g8\ \text{g} of oxygen gas O2\text{O}_2 (Mr=32M_r = 32): n=832=0.25 moln = \dfrac{8}{32} = 0.25\ \text{mol}.
  • Cue. Find the mass of 3 mol3\ \text{mol} of water (Mr=18M_r = 18): mass =3×18=54 g= 3 \times 18 = 54\ \text{g}.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original4 marks(a) Calculate the relative formula mass of water, H2O\text{H}_2\text{O}. (b) Calculate the number of moles in 36 g36\ \text{g} of water. (Relative atomic masses: H=1\text{H} = 1, O=16\text{O} = 16.)
Show worked answer →

(a) Add the relative atomic masses: two hydrogens and one oxygen.

Mr=(2×1)+16=2+16=18M_r = (2 \times 1) + 16 = 2 + 16 = 18.

(b) Moles = mass divided by relative formula mass:

n=3618=2 moln = \dfrac{36}{18} = 2\ \text{mol}.

What markers reward: adding the atomic masses correctly (counting two hydrogens), the mole formula, and the answer 2 mol2\ \text{mol}.

Original3 marksA sample contains 0.5 mol0.5\ \text{mol} of carbon dioxide, CO2\text{CO}_2. (Relative atomic masses: C=12\text{C} = 12, O=16\text{O} = 16.) (a) Find the relative formula mass. (b) Find the mass of the sample.
Show worked answer →

(a) Mr=12+(2×16)=12+32=44M_r = 12 + (2 \times 16) = 12 + 32 = 44.

(b) Rearrange moles = mass divided by MrM_r to get mass = moles times MrM_r:

mass=0.5×44=22 g\text{mass} = 0.5 \times 44 = 22\ \text{g}.

What markers reward: the relative formula mass of 4444, rearranging the mole formula, and the mass 22 g22\ \text{g}.

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