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How does the discriminant tell us how many real roots a quadratic equation has, without solving it?

Use the discriminant b squared minus 4ac to determine the nature of the roots of a quadratic equation and apply it to find unknown constants

A focused answer to the N(A)-Level Additional Mathematics outcome on the discriminant. Use b squared minus 4ac to decide whether a quadratic has two, one, or no real roots, and to find unknown constants from a root condition.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
  4. Try this

What this dot point is asking

SEAB wants you to use the discriminant of a quadratic equation, the quantity b2−4acb^2 - 4ac, to decide how many real roots the equation has without actually solving it. You also need to run the idea backwards: given a condition such as "equal roots" or "no real roots", form an equation or inequality in an unknown constant and solve for it. The discriminant is the part of the quadratic formula that sits under the square-root sign, which is exactly why it controls the number of solutions.

The answer

Where the discriminant comes from

The roots of ax2+bx+c=0ax^2 + bx + c = 0 (with a≠0a \ne 0) are given by the quadratic formula:

x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}

The expression under the square root, b2−4acb^2 - 4ac, is called the discriminant, often written as Δ\Delta (the Greek letter delta). Its sign decides what happens to the ± \pm\sqrt{\ } part.

The three cases

  • b2−4ac>0b^2 - 4ac > 0: the square root is a positive number, so ±\pm gives two different values. The equation has two real and distinct roots, and the graph crosses the xx-axis twice.
  • b2−4ac=0b^2 - 4ac = 0: the square root is zero, so both signs give the same value. The equation has one repeated (equal) root, and the graph just touches the xx-axis.
  • b2−4ac<0b^2 - 4ac < 0: you would be taking the square root of a negative number, which has no real value. The equation has no real roots, and the graph does not meet the xx-axis at all.

Running it backwards to find a constant

Many questions give you a quadratic containing an unknown letter and a condition on the roots. Translate the condition into the discriminant:

  • "two distinct (or two real) roots" gives b2−4ac>0b^2 - 4ac > 0,
  • "equal roots" (or "a repeated root", or "the line is a tangent") gives b2−4ac=0b^2 - 4ac = 0,
  • "no real roots" gives b2−4ac<0b^2 - 4ac < 0.

Then substitute aa, bb and cc in terms of the unknown and solve the resulting equation or inequality.

Identify a, b and c carefully

Always write the equation as ax2+bx+c=0ax^2 + bx + c = 0 first, including any signs. A negative coefficient is a frequent source of error, since b2b^2 makes the sign of bb vanish but the term 4ac4ac keeps the signs of aa and cc.

Examples in context

Example 1. Tangency to a curve. A straight line meets a parabola where their equations are equal. Setting them equal produces a quadratic; if the line is a tangent, that quadratic has equal roots, so b2−4ac=0b^2 - 4ac = 0. The discriminant turns a geometric tangency condition into one tidy algebraic equation, which is why it appears in coordinate-geometry questions too.

Example 2. Guaranteeing real solutions. An engineer models a system with x2−6x+c=0x^2 - 6x + c = 0 and needs the model to have real solutions for it to be physically meaningful. The condition is b2−4ac≥0b^2 - 4ac \ge 0, that is 36−4c≥036 - 4c \ge 0, so c≤9c \le 9. The discriminant sets the exact range of the constant for which real answers exist.

Try this

Q1. Find the discriminant of 3x2+2x−1=03x^2 + 2x - 1 = 0 and state the nature of its roots. [2 marks]

  • Cue. b2−4ac=22−4(3)(−1)=4+12=16>0b^2 - 4ac = 2^2 - 4(3)(-1) = 4 + 12 = 16 > 0, so two real and distinct roots.

Q2. The equation x2−8x+c=0x^2 - 8x + c = 0 has equal roots. Find cc. [2 marks]

  • Cue. Set b2−4ac=0b^2 - 4ac = 0: 64−4c=064 - 4c = 0, so c=16c = 16.

Q3. Show that x2+x+1=0x^2 + x + 1 = 0 has no real roots. [2 marks]

  • Cue. b2−4ac=1−4=−3<0b^2 - 4ac = 1 - 4 = -3 < 0, so there are no real roots.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Original3 marksWithout solving, determine the nature of the roots of 2x2−5x+1=02x^2 - 5x + 1 = 0.
Show worked answer →

Identify a=2a = 2, b=−5b = -5, c=1c = 1.

Discriminant: b2−4ac=(−5)2−4(2)(1)=25−8=17b^2 - 4ac = (-5)^2 - 4(2)(1) = 25 - 8 = 17.

Since 17>017 > 0, the equation has two real and distinct roots.

What markers reward: correct identification of aa, bb and cc (note b=−5b = -5), accurate substitution into b2−4acb^2 - 4ac, and a conclusion that matches the sign (positive gives two distinct real roots).

Original4 marksThe equation x2+kx+9=0x^2 + kx + 9 = 0 has equal roots. Find the possible values of kk.
Show worked answer →

Equal roots means the discriminant is zero: b2−4ac=0b^2 - 4ac = 0.

Here a=1a = 1, b=kb = k, c=9c = 9, so k2−4(1)(9)=0k^2 - 4(1)(9) = 0, giving k2−36=0k^2 - 36 = 0.

Then k2=36k^2 = 36, so k=6k = 6 or k=−6k = -6.

What markers reward: setting the discriminant to zero for equal roots, substituting correctly, and giving both values of kk (a common slip is to drop the negative root).

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