Kinematics quiz: N(A)-Level Additional Mathematics (SEAB 4051) quiz

In straight-line motion, velocity is the rate of change of:

Acceleration is the rate of change of:

A particle is instantaneously at rest when:

Given $s = t^2 - 4t$, find the velocity $v$.

Given $s = t^2 - 4t$, find the acceleration $a$.

A particle has $v = 2t - 6$. When is it at rest?

Going from acceleration to velocity, you must:

When you integrate acceleration to find velocity, you must also:

A particle has $a = 6t$ and $v = 4$ at $t = 0$. Find $v$.

A particle has $v = 3t^2$ and $s = 0$ at $t = 0$. Find the displacement $s$.

A positive velocity tells you the particle is:

If acceleration is zero throughout the motion, the velocity is:

A particle has $s = t^3 - 6t$. Find the velocity at $t = 2$.

To find when a particle changes direction, you solve: