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How do the seven SI base quantities and their units provide a consistent foundation for every physical measurement?

Recall the SI base quantities and their units, express derived units as products or quotients of base units, and use base units to check the homogeneity of physical equations

A focused answer to the H2 Physics Measurement learning outcome on SI base quantities and units. The seven base quantities, how derived units are built from them, and how to check an equation for homogeneity using base units.

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  2. The answer
  3. Examples in context
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What this dot point is asking

SEAB wants you to know the seven SI base quantities and their units, to express any derived unit (newton, joule, pascal and so on) as a product or quotient of base units, and to use base units to test whether a physical equation is homogeneous. This is the foundation of every numerical answer in H2 Physics, and homogeneity checks appear in Paper 1, Paper 2 and the data analysis of Paper 3.

The answer

The seven base quantities

Every physical quantity in the syllabus is built from seven base quantities, each with one SI base unit.

Base quantity Symbol SI base unit Unit symbol
Mass mm kilogram kg
Length ll metre m
Time tt second s
Electric current II ampere A
Thermodynamic temperature TT kelvin K
Amount of substance nn mole mol
Luminous intensity IvI_v candela cd

For H2 Physics, the first six matter constantly; the candela is rarely used in calculations.

Derived units from base units

A derived unit is any combination of base units. You build it by substituting the defining equation of the quantity.

  • Speed: v=distancetimev = \dfrac{\text{distance}}{\text{time}}, so [v]=m s1[v] = \text{m s}^{-1}.
  • Force: F=maF = ma, so [F]=kg×m s2=kg m s2[F] = \text{kg} \times \text{m s}^{-2} = \text{kg m s}^{-2}. This combination is named the newton, N\text{N}.
  • Energy: E=FdE = Fd, so [E]=kg m s2×m=kg m2s2[E] = \text{kg m s}^{-2} \times \text{m} = \text{kg m}^2\text{s}^{-2}, named the joule, J\text{J}.
  • Power: P=EtP = \dfrac{E}{t}, so [P]=kg m2s3[P] = \text{kg m}^2\text{s}^{-3}, named the watt, W\text{W}.
  • Pressure: p=FAp = \dfrac{F}{A}, so [p]=kg m1s2[p] = \text{kg m}^{-1}\text{s}^{-2}, named the pascal, Pa\text{Pa}.
  • Electric charge: Q=ItQ = It, so [Q]=A s[Q] = \text{A s}, named the coulomb, C\text{C}.

Homogeneity of equations

An equation is homogeneous (dimensionally consistent) if every additive term has the same base units. To test it:

  1. Write the left side in base units.
  2. Write each term on the right side in base units.
  3. If they all match, the equation is homogeneous.

[LHS]=[each term of RHS][\text{LHS}] = [\text{each term of RHS}]

Homogeneity is a quick error-check: if the units do not match, the equation is definitely wrong. The converse is not guaranteed, which is the key subtlety examiners probe.

What homogeneity cannot catch

A homogeneous equation may still be wrong. Three things slip through:

  • A wrong pure-number coefficient (such as a missing factor of 12\frac{1}{2} or 2π2\pi), because pure numbers carry no units.
  • A missing dimensionless term added to a correct one.
  • An error inside a function whose argument must be dimensionless (such as sin\sin, ln\ln or exe^x).

So homogeneity is a necessary condition for correctness, not a sufficient one.

Examples in context

Example 1. Checking a drag equation. A student writes the terminal velocity of a sphere as v=2r2(ρsρf)g9ηv = \dfrac{2 r^2 (\rho_s - \rho_f) g}{9 \eta}. The right side has units m2kg m3m s2kg m1s1=kg m0s2kg m1s1=m s1\dfrac{\text{m}^2 \cdot \text{kg m}^{-3} \cdot \text{m s}^{-2}}{\text{kg m}^{-1}\text{s}^{-1}} = \dfrac{\text{kg m}^0 \text{s}^{-2}}{\text{kg m}^{-1}\text{s}^{-1}} = \text{m s}^{-1}, which matches a velocity. The equation passes the homogeneity test.

Example 2. Spotting an error. A candidate proposes kinetic energy as Ek=mvE_k = m v. Base units give kgm s1=kg m s1\text{kg} \cdot \text{m s}^{-1} = \text{kg m s}^{-1}, which is momentum, not energy (kg m2s2\text{kg m}^2\text{s}^{-2}). The homogeneity check immediately flags the missing factor of vv, steering the student to Ek=12mv2E_k = \frac{1}{2}mv^2.

Try this

Q1. State the seven SI base quantities and their units. [3 marks]

  • Cue. Mass (kg), length (m), time (s), current (A), thermodynamic temperature (K), amount of substance (mol), luminous intensity (cd).

Q2. Express the joule and the watt in SI base units. [2 marks]

  • Cue. J=kg m2s2\text{J} = \text{kg m}^2\text{s}^{-2}, W=kg m2s3\text{W} = \text{kg m}^2\text{s}^{-3}.

Q3. The power radiated by a black body is modelled as P=σAT4P = \sigma A T^4, where AA is area and TT is temperature. Determine the base units of the constant σ\sigma. [3 marks]

  • Cue. [σ]=[P][A][T4]=kg m2s3m2K4=kg s3K4[\sigma] = \dfrac{[P]}{[A][T^4]} = \dfrac{\text{kg m}^2\text{s}^{-3}}{\text{m}^2 \cdot \text{K}^4} = \text{kg s}^{-3}\text{K}^{-4}.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Specimen4 marksThe drag force on a sphere moving slowly through a fluid is modelled by F=kηrvF = k \eta r v, where η\eta is the viscosity of the fluid (units kg m1s1\text{kg m}^{-1}\text{s}^{-1}), rr is the radius of the sphere and vv is its speed. (a) Show that the constant kk is dimensionless. (b) Explain why a homogeneous equation is not necessarily a correct equation.
Show worked answer →

(a) Express both sides in base units and require them to match.

Left side, force: [F]=kg m s2[F] = \text{kg m s}^{-2}.

Right side: [ηrv]=(kg m1s1)(m)(m s1)=kg m s2[\eta r v] = (\text{kg m}^{-1}\text{s}^{-1})(\text{m})(\text{m s}^{-1}) = \text{kg m s}^{-2}.

Since the base units of ηrv\eta r v already equal those of FF, the constant kk must carry no units, so kk is dimensionless.

(b) Homogeneity only confirms that both sides share the same base units. It cannot detect a wrong dimensionless factor (for example a missing 12\frac{1}{2}), nor a missing dimensionless term, so a homogeneous equation can still be numerically wrong.

Markers reward correct base-unit substitution on both sides, the explicit conclusion that kk is dimensionless, and a clear statement that homogeneity is a necessary but not sufficient test.

Original3 marksThe pressure pp at depth hh in a liquid of density ρ\rho is given by p=ρghp = \rho g h. Use base units to verify that this equation is homogeneous.
Show worked answer →

Pressure is force per unit area, so [p]=kg m s2m2=kg m1s2[p] = \dfrac{\text{kg m s}^{-2}}{\text{m}^2} = \text{kg m}^{-1}\text{s}^{-2}.

Right side: [ρgh]=(kg m3)(m s2)(m)=kg m1s2[\rho g h] = (\text{kg m}^{-3})(\text{m s}^{-2})(\text{m}) = \text{kg m}^{-1}\text{s}^{-2}.

Both sides reduce to kg m1s2\text{kg m}^{-1}\text{s}^{-2}, so the equation is homogeneous.

Markers reward writing pressure in base units (not just Pa\text{Pa}), correct substitution for ρ\rho, gg and hh, and an explicit statement that the two sides match.

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