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How does the ideal gas equation describe gas behaviour, and when and why do real gases deviate from it?

State the ideal gas equation pV = nRT and use it in calculations including determination of molar mass, explain the assumptions of the kinetic theory, and account for the deviation of real gases from ideal behaviour at high pressure and low temperature

A focused answer to the H2 Chemistry learning outcome on gases. Using the ideal gas equation to find molar mass, the assumptions of kinetic theory, and a clear account of why real gases deviate at high pressure and low temperature in terms of molecular volume and intermolecular forces.

Generated by Claude Opus 4.88 min answer

Reviewed by: AI editorial process; not yet individually human-reviewed

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  1. What this dot point is asking
  2. The answer
  3. Examples in context
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What this dot point is asking

SEAB wants you to apply the ideal gas equation pV=nRTpV = nRT (especially to find a molar mass from vaporised-liquid data), state the assumptions behind the kinetic theory of an ideal gas, and explain in molecular terms why real gases deviate at high pressure and low temperature. The molar-mass calculation is a guaranteed Paper 2 skill.

The answer

The ideal gas equation

pV=nRTpV = nRT

where pp is pressure (Pa), VV is volume (m cubed), nn is amount (mol), R=8.31R = 8.31 J per mol per K, and TT is temperature (K). The single most common error is unit handling, so always convert before substituting:

  • pressure: kPa ×103\times 10^3 to Pa
  • volume: cm cubed ×106\times 10^{-6}, or dm cubed ×103\times 10^{-3}, to m cubed
  • temperature: degrees Celsius +273+ 273 to K

Finding molar mass

Since n=m/Mrn = m / M_r, substitute to get a working form:

pV=mMrRT    Mr=mRTpVpV = \frac{m}{M_r} RT \implies M_r = \frac{m R T}{p V}

This is how an unknown volatile liquid is identified: vaporise a known mass, measure the volume it occupies at known TT and pp, and solve for MrM_r.

The kinetic theory assumptions

An ideal gas is a model with these assumptions:

  1. Gas molecules are in constant, random motion.
  2. The molecules have negligible volume compared with the volume of the container.
  3. There are no intermolecular forces between molecules.
  4. Collisions are perfectly elastic (no kinetic energy is lost).
  5. The average kinetic energy is proportional to the absolute temperature.

Why real gases deviate

Two of the assumptions fail for real gases, and the deviation grows under two conditions:

At high pressure, molecules are forced close together. Their own volume is no longer negligible compared with the container, so the real volume available is smaller than assumed, and the measured pV/nRTpV/nRT rises above 1.

At low temperature (and moderate pressure), molecules move slowly and intermolecular attractions become significant. Attractions pull molecules inward, so they strike the walls less forcefully and the measured pressure is below the ideal value, making pV/nRTpV/nRT dip below 1.

A gas behaves most ideally at high temperature and low pressure, where molecules are far apart and fast moving, so both volume and force effects are negligible.

Which gases are most ideal

Small, light, weakly interacting gases (He, H2\text{H}_2, Ne) are closest to ideal. Larger, more polarisable, or polar molecules (CO2\text{CO}_2, NH3\text{NH}_3, SO2\text{SO}_2) deviate more because of stronger intermolecular forces and greater molecular volume.

Examples in context

Example 1. Verifying a gas law in the lab. A JC practical asks students to confirm pV=nRTpV = nRT by vaporising a measured mass of propanone in a gas syringe in a water bath. Plugging the measured volume, temperature, and atmospheric pressure into Mr=mRT/(pV)M_r = mRT/(pV) should return a value near 5858 g per mol. A value much higher usually means some liquid failed to vaporise; a value much lower usually means a leak in the syringe.

Example 2. Predicting deviation in industry. In the Haber process, nitrogen and hydrogen are compressed to about 200200 atmospheres. At such high pressure the gases deviate significantly from ideal behaviour, and engineers use real-gas corrections (such as the van der Waals equation, beyond H2 syllabus detail) rather than pV=nRTpV = nRT when designing the reactor. This connects the abstract deviation idea to a context met later in equilibrium.

Try this

Q1. Calculate the volume occupied by 0.500.50 mol of an ideal gas at 300300 K and 120120 kPa. [2 marks]

  • Cue. V=nRT/p=(0.50×8.31×300)/120000=1.04×102V = nRT/p = (0.50 \times 8.31 \times 300)/120000 = 1.04 \times 10^{-2} m cubed (about 10.410.4 dm cubed).

Q2. State two assumptions of the kinetic theory of an ideal gas that fail for a real gas. [2 marks]

  • Cue. Negligible molecular volume; no intermolecular forces.

Q3. Explain why a fixed mass of gas approaches ideal behaviour as temperature is raised at constant pressure. [3 marks]

  • Cue. Higher TT means faster molecules and larger volume, so molecules spend less time close together; intermolecular forces and molecular volume become negligible relative to the total volume.

Exam-style practice questions

Practice questions written in the style of SEAB exam questions on this dot point, with worked answer explainers. The year tag is the paper they imitate, not the source.

Specimen (9729)4 marksA 0.250 g sample of a volatile liquid was vaporised and found to occupy 102 cm cubed at 98 degrees Celsius and 101 kPa. Calculate the molar mass of the liquid. (R = 8.31 J per mol per K.)
Show worked answer →

Use pV = nRT, then Mr = mass / moles.

Convert units: p=101000p = 101\,000 Pa, V=102×106V = 102 \times 10^{-6} m cubed, T=98+273=371T = 98 + 273 = 371 K.

n=pVRT=101000×102×1068.31×371n = \dfrac{pV}{RT} = \dfrac{101\,000 \times 102 \times 10^{-6}}{8.31 \times 371}

n=10.303083=3.34×103n = \dfrac{10.30}{3083} = 3.34 \times 10^{-3} mol.

Mr=massn=0.2503.34×103=74.8M_r = \dfrac{\text{mass}}{n} = \dfrac{0.250}{3.34 \times 10^{-3}} = 74.8 g per mol.

So the molar mass is about 7575 g per mol.

Markers reward correct SI unit conversions, the rearrangement of pV = nRT, and the final molar mass with units.

2021 (style)3 marksExplain, in terms of the assumptions of the kinetic theory, why carbon dioxide deviates more from ideal behaviour than helium at the same temperature and pressure.
Show worked answer →

Two ideal-gas assumptions fail for real gases: that molecules have negligible volume, and that there are no intermolecular forces.

CO2 molecules are larger and have more electrons than helium atoms, so they have stronger intermolecular (van der Waals) forces and a larger molecular volume.

Stronger forces mean the measured pressure is lower than the ideal value (molecules attract each other and hit the walls less hard), and the larger molecular volume makes the available volume smaller than assumed.

Helium is a small, monatomic species with very weak forces, so it behaves much more ideally.

Therefore CO2 deviates more than He under the same conditions.

Markers reward naming the two failed assumptions, the comparison of size and intermolecular forces, and linking each to the direction of deviation.

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